12x^2-48x+44=0

Solution for 12x^2-48x+44=0 equation:

12x^2-48x+44=0

a = 12; b = -48; c = +44;
Δ = b2-4ac
Δ = -482-4·12·44
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-8\sqrt{3}}{2*12}=\frac{48-8\sqrt{3}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+8\sqrt{3}}{2*12}=\frac{48+8\sqrt{3}}{24}
$